Answer to Question #1356 in Mechanics | Relativity for Jon ALlen

Question #1356
A visitor to a lighthouse wishes to determine the height of the tower. She ties a spool of thread to a small rock to make a simple pendulum, which she hangs down the center of a spiral staircase of the tower. The period of oscillation is 10.8 s. The acceleration of gravity is 9.8 m/s2 . What is the height of the tower? Answer in units of m.
1
Expert's answer
2011-01-18T02:46:28-0500
The formula for the period of oscillations can be written as
T = 2 π √(L/g)

L = gT2/4 π2
L = 9.8*10.82 / 4π2 = 28.95 m.

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Comments

Assignment Expert
11.12.19, 16:29

Dear D, this "center" means the space between the spiral stairs of the tower. So, you don't need to multiply the answer by two.

D.
10.12.19, 19:28

I thought since it says “center” maybe we should multiply the final answer by two, since center is half way through and they want the full height.

Thanks!

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