Question #125867

a pully system has a two boxes. box 1 is on a ledge and has a mass of 2.0×10 to the power of 3 kg, box 2 is attached by a rope at a 90° angle blow box one and has a mass of 4.4×10 to the power of 2 kg. There is a man standing on box number two, what is the apparent weight of the man if all surfaces are frictionless?

Expert's answer

According to the second Newton's law

"Ma=T"

"mg-T=ma"

"m_1g-N=m_1a"

So, we get

"N=m_1g-m_1\\frac{mg}{M+m}"

Assume that the man has a mass "m_1=60 kg" . Finally

"P=N=m_1g-m_1\\frac{mg}{M+m}=60\\cdot9.81-60\\cdot\\frac{440\\cdot9.81}{2000+440}=482 N"

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