Answer to Question #125867 in Mechanics | Relativity for Sammy W-S

Question #125867
a pully system has a two boxes. box 1 is on a ledge and has a mass of 2.0×10 to the power of 3 kg, box 2 is attached by a rope at a 90° angle blow box one and has a mass of 4.4×10 to the power of 2 kg. There is a man standing on box number two, what is the apparent weight of the man if all surfaces are frictionless?
1
Expert's answer
2020-07-10T10:22:46-0400


According to the second Newton's law


"Ma=T"

"mg-T=ma"

"m_1g-N=m_1a"


So, we get


"N=m_1g-m_1\\frac{mg}{M+m}"


Assume that the man has a mass "m_1=60 kg" . Finally


"P=N=m_1g-m_1\\frac{mg}{M+m}=60\\cdot9.81-60\\cdot\\frac{440\\cdot9.81}{2000+440}=482 N"






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