Answer to Question #117855 in Mechanics | Relativity for Aana

Question #117855
A man cleaning his apartment pulls a vacuum with a force of 50N at an angle of 30°. A friction force of 40N retards the motion and the vacuum cleaner is pulled a horizontal distance of 3m. Calculate the net work done by the 50N pull
1
Expert's answer
2020-05-25T10:48:13-0400

Solution.

"F_p=50N;"

"\\varTheta=30^o;"

"F_f=40N;"

"d=3m;"

"W-?;"

"W=Fcos\\varTheta d;"

Traction force work: "W_p=50N\\sdot0.866\\sdot3m=130J;"

Work of friction force (angle is equal to 180o): "W_f=40N\\sdot(-1)\\sdot3m=-120J;"

Net work:

"W=W_p+W_f;"

"W=130J-120J=10J;"

Answer: "W=10J."


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