Question #113906

A motorist is travelling at 15 m/s when he sees a child run into the road. He brakes and

the car comes to rest in 0.75 s.

a) Draw a velocity time graph to show the deceleration, and use your graph to

calculate the distance travelled once the brakes are applied [4]

b) The deceleration of the car.

the car comes to rest in 0.75 s.

a) Draw a velocity time graph to show the deceleration, and use your graph to

calculate the distance travelled once the brakes are applied [4]

b) The deceleration of the car.

Expert's answer

Due to the constant deceleration, the velocity decreases linearly over time. Let "V_0" be the initial velocity and "a" be the deceleration. Since the velocity decreases, "a" is negative. We may write the formula for velocity "V(t) = V_0 + at" .

(a) At the end of moving the velocity is equal to 0. The displacement of motorist is the area under the curve representing the dependence of velocity on time. This area is the area of a triangle, so we may write the expression

"S=\\dfrac12\\cdot V_0\\cdot t = \\dfrac12\\cdot15\\,m\/s\\cdot0.75\\,s = 5.625\\,m" .

(b) Let us calculate the deceleration. "V(0.75) = 0\\,m\/s, \\;\\; V(0.75) = 15\\,m\/s+ a\\cdot0.75\\,s," so

"a = \\dfrac{0\\,m\/s-15\\,m\/s}{0.75\\,s} = -20\\, m\/s^2."

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