Question #113108

A spaceman jumps from an airplane. After he had fallen 35 m, then his parachute opens. Now he falls with retardation of 1.8 m/s² and reaches the earth with a velocity of 2.7 m/s. What was the height of the airplane?

Expert's answer

The speed of a spaceman after he had fallen 35 m

"v_i=\\sqrt{2gh}=\\sqrt{2\\times 9.8\\times 35}=26.2\\:\\rm m\/s"The distance traveled by spaceman when he falls with retardation

"d=\\frac{v_f^2-v_i^2}{2a}=\\frac{2.7^2-26.2^2}{2\\times (-1.8)}=189\\:\\rm m"Finally, the height of the airplane

"H=h+d=35+189=224\\:\\rm m."
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