A hydraulic press has two pistons, where the diameter of one of them is double that of the other, when the small piston is affected by pressure P, the pressure affects the big piston will be
1
Expert's answer
2020-03-25T11:18:54-0400
The Force should be equal for both pistons, so
"P*S=const"
where "P" - pressure and "S" - square
"P_1=P" for small piston
Since "D_2\/D_1=2" , then "S_2\/S_1=(D_2\/D_1)^2=4"
Then pressure in big piston will be "P_2=P_1S_1\/S_2=P\/4"
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