Question #105237

A boy of mass 40kg slides down a chute inclined at 30 degrees to the horizontal. If the chute is smooth and the boy starts from rest, with what velocity does he pass a point 5 m from the starting point?

Expert's answer

"mg\\sin\\alpha=ma"

"a=g\\sin\\alpha"

"S=\\frac{v^2}{2a} \\to v=\\sqrt{2gS\\sin\\alpha}="

"=\\sqrt{2\\cdot 9.81\\cdot 5\\cdot\\sin30\u00b0}=7" m/s. **Answer**

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