Question #102577

The equation of transverse wave on a rope is

y(x, t) = 7 sin (4.0t − 0.02x)

where y and x are measured in cm and t is expressed in second. Calculate the

maximum speed of a particle on the rope. (5)

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y(x, t) = 7 sin (4.0t − 0.02x)

where y and x are measured in cm and t is expressed in second. Calculate the

maximum speed of a particle on the rope. (5)

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Expert's answer

_{max }=Aw where A - amplitude, w-frequency. From y(x,t)=7sin(4.0t-0.02x) , A=0.07 m , w=4.0 => V_{max}=0.07*4=0.28

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