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# Answer to Question #102391 in Mechanics | Relativity for sridhar

Question #102391
A solid sphere of mass 100 kg and radius 10 m moving in a space becomes a circular disc of radius 20 m in one hour. Then the rate of change of moment of inertia in the process is
1
2020-02-06T08:32:00-0500

moment of inertia of sphere:

"I=\\frac{2}{5} mr \\raisebox{0.45em}{2}"

moment of inertia of a circular disk:

"I'=\\frac{1}{2} mR\\raisebox{0.45em}{2}"

The rate of change of moment of inertia in the process is:

"\\frac{I'-I}{t}=\\frac{\\frac{1}{2} mR\\raisebox{0.45em}{2} - \\frac{2}{5} mr\\raisebox{0.45em}{2}}{t} = m\\frac{\\frac{1}{2} R\\raisebox{0.45em}{2} - \\frac{2}{5} r\\raisebox{0.45em}{2}}{t}"

"\\frac{I'-I}{t}= 100\\frac{\\frac{1}{2}* 20\\raisebox{0.45em}{2} - \\frac{2}{5}*10\\raisebox{0.45em}{2}}{3600} = 4.44"

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