A fraction of atoms of radioactive element that decays in 6 days is 7/8 . The fraction that decays in 10 days will be (a). 77/80. (b) 71/80. (c) 31/32. (d) 15/16
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Dear Edward, 7/8 indicates the fraction of decayed elements to the
initial number of active elements. But fraction N/N_0 shows the
fraction of active elements at the moment t. So we need calculate:
(N/N_0)_1 = 1 - 7/8 = 1/8.
Edward
23.08.18, 14:12
In question their is fraction of atom is 7/8 but in answer you are
using 1/8 why??
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Dear Edward, 7/8 indicates the fraction of decayed elements to the initial number of active elements. But fraction N/N_0 shows the fraction of active elements at the moment t. So we need calculate: (N/N_0)_1 = 1 - 7/8 = 1/8.
In question their is fraction of atom is 7/8 but in answer you are using 1/8 why??
Leave a comment