# Answer to Question #66856 in Electromagnetism for Chelsea

Question #66856

I can’t believe that after all these problems you are still making things! It’s great for

me, because I get to have you do calculations on them. This time, you are making a

solenoid. Naturally, you use a toilet paper tube.3 The tube has a diameter of 4.00 cm

and a height of 11.2 cm. You wrap it with copper wire having a cross-sectional area

of 1.02 × 10−6 m2

(20-gauge; note that the resistivity of copper is 1.70 × 10−8 Ωm ).

Your resulting solenoid has 98 loops. Determine (a) the current required to produce a

magnetic field of 6.00 mT in the center of the solenoid, and (b) the power required to

deliver this magnetic field.

me, because I get to have you do calculations on them. This time, you are making a

solenoid. Naturally, you use a toilet paper tube.3 The tube has a diameter of 4.00 cm

and a height of 11.2 cm. You wrap it with copper wire having a cross-sectional area

of 1.02 × 10−6 m2

(20-gauge; note that the resistivity of copper is 1.70 × 10−8 Ωm ).

Your resulting solenoid has 98 loops. Determine (a) the current required to produce a

magnetic field of 6.00 mT in the center of the solenoid, and (b) the power required to

deliver this magnetic field.

Expert's answer

a) A field of a solenoid is B = mm0*In or I = B/(mm0n) = 5.5A

b) The power of solenoid P = I^2*n*3.14*d*res./S = 6.2 W

b) The power of solenoid P = I^2*n*3.14*d*res./S = 6.2 W

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