# Answer on Electromagnetism Question for Cameron

Question #18296

What is the radius of the path of an electron whose speed is 1x10^7 m/s in a magnetic field of magnitude 0.020 T when velocity is perpendicular to magnetic field?

Expert's answer

Lorentz force is equal to centrifugal acceleration * mass

mv^2/r = qvB

Hence

r = mv/(qB) = 9.1*10^(-31)*10^7/(1.6*10^(-19)*0.02) = 0.003ΠΌ

mv^2/r = qvB

Hence

r = mv/(qB) = 9.1*10^(-31)*10^7/(1.6*10^(-19)*0.02) = 0.003ΠΌ

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment