Answer to Question #1487 in Electromagnetism for Ryan

Question #1487
Because high-temperature superconducting cables cannot sustain high currents, their applicability is limited. However, a prototype of a high-temperature superconductor that can transfer a charge of 1.8 x 10^5 C in 6.0 min has been constructed. To what current does this correspond?
1
Expert's answer
2011-02-07T06:53:01-0500
I = Q/t [C/sec]
I = 1.8x105 /(6*60) = 500 A.

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