Answer to Question #5476 in Electric Circuits for jessica
V = 30 m/s;
a = 4 m/s^2;
L = 400m.
V = a*T ==> T = V/a = 30/4 = 7.5 s - time needed the train to stop.
S = V*T - (a*T^2)/2 = 30*7.5 - (4*7.5^2)/2 = 112.5 - stopping distance.
S < L, so the train will stop in time.
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