Question #4124

Two bodies are made to fall from two different heights in the ratio 9:4.what will be the ratio of their times of fall?

Expert's answer

Referring to the equations of the motion we can write the following expressions for the heights and the falling times:

H = gt2/2, where g is the gravitational acceleration.

thus

H_{1}: H_{2} = gt_{1}^{2}/2 : gt_{2}^{2}/2 = t_{1}^{2} : t_{2}^{2}

9 : 4 =t_{1}^{2} : t_{2}^{2}

t_{1} : t_{2} = 3 : 2

H = gt2/2, where g is the gravitational acceleration.

thus

H

9 : 4 =t

t

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