Question #33298

why is the terminal voltage of the cell less than it's emf ?

Expert's answer

All sources have a non-zero effective internal resistance, that's why all sources have voltage drop on internal resistance.

U = E - Ur, where

U is terminal voltage,

E is EMF,

Ur is voltage drop on internal resistance,

Ur=I*r, where r is internal resistance.

U = E - Ur, where

U is terminal voltage,

E is EMF,

Ur is voltage drop on internal resistance,

Ur=I*r, where r is internal resistance.

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