# Answer to Question #14146 in Electric Circuits for Deven

Question #14146

A circuit consists of a 100 Ω resistor, a 5 V battery, and an LED placed correctly and all in series. The voltage drop across the LED is 2 V. What is the current through the LED?

Expert's answer

Total voltage drop is 5 V. So, the voltage drop across the resistor is

Ur = 5

- 2 = 3 V.

The current in a circuit is I = Iled = Ir = Ur / R = 3 / 100 =

0.03 A.

Ur = 5

- 2 = 3 V.

The current in a circuit is I = Iled = Ir = Ur / R = 3 / 100 =

0.03 A.

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