# Answer to Question #83288 in Classical Mechanics for prince

Question #83288

The displacement of a particle executing simple harmonic motion is given by x=0.01cos4π(t+0.0625)m. Deduce the period of the motion.

a.1.0 s

b. 0.1 s

c. 2.5 s

d. 0.5 s

a.1.0 s

b. 0.1 s

c. 2.5 s

d. 0.5 s

Expert's answer

The equation of motion for particle executing simple harmonic motion

x=x_max cos〖(ωt+ϕ_0 )=x_max cos(2π/T t+ϕ_0 ) 〗=0.01 cos〖4π(t+0.0625) 〗

Therefore, the period of the motion

T=1/2 s=0.5 s

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