Answer to Question #71127 in Classical Mechanics for Neil
D = R2 - R,
R2 = (1/3)*w(t^3)gcos(k) - w*(t^2)*V*sin(a)*cos(k) + Vcos(a)*t
R = 2(V^2)(sin(a)^2)/g
I know what D is but not how to get there,
D = ((2(R^3)/g)^(1/2))*wcos(k)[(cot(a)^(1/2)) - 1/3*f(a)]
f(a) is a function of a, it is known to be tan(a)^3/2 but the question is initially phrased this way.
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