Answer to Question #18711 in Atomic and Nuclear Physics for Dalton McGerr
E = hf
where f is the frequency of the photon and h is Planck's constant (6.626 x 10E-34 J s).
Substituting f = 2.22 x 10E14 s-¹ gives E = 1.47 x10E-19 J (to 3 sf).
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