Answer to Question #120398 in Other for Nimra

Question #120398
an electron at pointing in the figure has a speed v of 1.41 E 6 m/s find (a )the magnitude and direction of the magnetic field that will cause the electron to flow the semicircular path from A to B and( b) the time required for the electron to move from A to B.
1
Expert's answer
2020-06-08T19:09:15-0400


a) At A, magnetic force should be towards right. Thus from Fleming's left hand rule magnetic field should be inwards (into a paper).

The electron experiences centripetal force under the action of magnetic field. Hence


"{m_ev_0^2\\over r}=|e|v_0B=>B={m_ev_0\\over |e|r}"

"B={9.11\\times10^{-31}kg\\cdot 1.41\\times 10^6 m\/s\\over 1.6\\times 10^{-19}C\\cdot 0.05m}=1.61\\times 10^{-4}T"

b)


"t={\\pi r\\over v_0}={\\pi\\cdot 0.05 m\\over 1.4\\times 10^6 m\/s}=1.12\\times10^{-7}s=0.112 \\mu s"


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS