# Answer to Question #9943 in Trigonometry for Eliana Hernandez

Question #9943

solve each on the interval (0, 2pi)

1. 2cos^2(x)-3cos(x)+1=0

2. 2sin^2(x)+cos(x)=1

3. cos(x)=-0.8092

1. 2cos^2(x)-3cos(x)+1=0

2. 2sin^2(x)+cos(x)=1

3. cos(x)=-0.8092

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