63 814
Assignments Done
99,5%
Successfully Done
In August 2018

Answer to Question #9824 in Trigonometry for Richard Johnson

Question #9824
Hi I am really struggling with this:

Re-write the expression 5.5 Cos t + 7.8 Sin t, in the form R sin (t+α).

Any help would be greatly appreciated as im pulling my hair out with this now!
Expert's answer
5.5 Cos t + 7.8 Sin t=sqrt(5.5^2+7.8^2)*(Cos t *5.5/sqrt(5.5^2+7.8^2)+Sin t *7.8 /sqrt(5.5^2+7.8^2))

sqrt(5.5^2+7.8^2)= approx. 9.5

so we have
5.5 Cos t + 7.8 Sin t=9.5*(Cos t *5.5/9.5+Sin t *7.8 /9.5)
We can denote 5.5/9.5=sin(theta), 7.8 /9.5=cos(theta) because& 7.8^2+5.5^2=9.5^2 therefore sin(theta^2)+cos(theta)^2=1 so that's all right
now we can use formula fopr sine of the sum:
5.5 Cos t + 7.8 Sin t=9.5*(Cos t *5.5/9.5+Sin t *7.8 /9.5)=9.5 sin(t+theta) where theta is defined above

In your denotations it will be 5.5 Cos t + 7.8 Sin t=R sin(t+α) where R=9.5, sin α=5.5/9.5, cos α=7.8 /9.5

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

Submit
Privacy policy Terms and Conditions