# Answer to Question #20661 in Trigonometry for janus

Question #20661

the westward and southward components of the velocity of a shipare 67 knots and 12.5 knots respectively. find the speed of the ship and direction in which she is sailing

Expert's answer

According to the Pythagoras' theorem, the speed of the ship is

S = √((67[knot])² + (12.5[knot])²) ≈ 68.156[knot].

Direction of the ship is

α = π + cos

(counting from the north as zero degree).

S = √((67[knot])² + (12.5[knot])²) ≈ 68.156[knot].

Direction of the ship is

α = π + cos

^{-1}(12.5[knot]/68.156[knot]) ≈ 259°43'(counting from the north as zero degree).

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