Answer to Question #11800 in Trigonometry for tanya jaiswal

Question #11800
Sinx/Cos3x+Sin3x/Cos9x+Sin9x/Cos27x=1/2(tan27x-tanx)
√3Cosec20°-Sec20°=4
1
Expert's answer
2012-07-13T08:32:34-0400

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