# Answer to Question #11460 in Trigonometry for akmal

Question #11460

Cos70=h and sin35=k, express in terms of h and/or k,

Cos149=?

Cos149=?

Expert's answer

sin(35)cos(70)cos(149)=(sin(35+70-149)+sin(149+70-35)+sin(149+35-70)-sin(35+70+149))/4=(sin(-44)+sin(184)+sin(114)-sin(254))/4

cos(149)=(sin(-44)+sin(184)+sin(114)-sin(254))/(4kh)

cos(149)=(sin(-44)+sin(184)+sin(114)-sin(254))/(4kh)

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