69 767
Assignments Done
Successfully Done
In February 2019

Answer to Question #10053 in Trigonometry for archana meena

Question #10053
Expert's answer
This is not identity.
If we have 1/(secA+tanA)=(1-secA)/cosA then it is equal
to cosA/(sinA+cosA)=(cosA-1)/cos^2(A)
If we put A=60 degrees then cosA=1/2
and sinA=sqrt(3)/2.
In left part of identity we'll get 1/(sqrt(3)+1) and for
the right part -2. They are not equal.

If we omit parenthesis
1/secA+tanA=1-secA/cosA then it's equivalent to (cos^2(A)+sinA)/cosA=
Similar way we'll get again not equal parts.

it is error in given statement.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


No comments. Be first!

Leave a comment

Ask Your question

Privacy policy Terms and Conditions