57 593
Assignments Done
Successfully Done
In February 2018
Your physics homework can be a real challenge, and the due date can be really close — feel free to use our assistance and get the desired result.
Be sure that math assignments completed by our experts will be error-free and done according to your instructions specified in the submitted order form.
Our experts will gladly share their knowledge and help you with programming homework. Keep up with the world’s newest programming trends.

Answer on Statistics and Probability Question for Neil Schliewe

Question #8101
If 2 cards are drawn from a normal deck of 52 cards, what is the probability that both cards will be spades?
Expert's answer
There 1/4*52 spades in the deck.Probability to pick a spade taking single card is 1/4. Due to multiplication rule probability to pick two cards-spades is 1/4*1/4=1/16

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


Assignment Expert
03.04.2012 08:21

In fact this question is a little bit tricky.

If we
consider drawing one card, putting it back in the deck, regardless if it
is a spade or not, then reshuffling the deck and drawing the second
card, the probability is 1/4 x 1/4 =1/16 This is the same as 1/4 x 1/4 = 1/16.Or we can consider experiment as picking two cards at a time. For each of them probability to turn out spade is 1/4.

On the other hand, if we draw firstly one card& it is spade with probability 1/4. If a second card drawn, there's one less spade in the deck, so the
probability on the second draw is 12/51.

The probability of
drawing two spades from a deck is 0.25 x 12/51 = 0.058824 This is called
sampling without replacement. In quality control, it is very common to
sample without replacement as bad parts are discarded.

Neil Schliewe
03.04.2012 08:12

Don't you have to account for the fact that this is a dependent event? Taking 2 cards the second card should be only 12/51 - correct?

Leave a comment

Ask Your question