Question #6164

QUESTION 2. Find the number of possible choices for a 2-digit password that is greater than 19. Then find the number of possible choices for a 4-digit Personal Identification Number (PIN) if the digits cannot be repeated.

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Assignment Expert12.01.20, 17:57The number of possible choices for a 3-digit PIN is {10}_A^{3}=10!/(10-3)!=10!/7!=10*9*8=720 if the digits cannot be repeated.

Keira10.01.20, 22:07Find the number of possible choices for a 3-digit PIN (personal identification number) if the digits cannot be repeated.

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