Answer to Question #6164 in Statistics and Probability for Jane

Question #6164
QUESTION 2. Find the number of possible choices for a 2-digit password that is greater than 19. Then find the number of possible choices for a 4-digit Personal Identification Number (PIN) if the digits cannot be repeated.
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Expert's answer
2012-01-31T09:34:54-0500
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Comments

Assignment Expert
12.01.20, 17:57

The number of possible choices for a 3-digit PIN is {10}_A^{3}=10!/(10-3)!=10!/7!=10*9*8=720 if the digits cannot be repeated.

Keira
10.01.20, 22:07

Find the number of possible choices for a 3-digit PIN (personal identification number) if the digits cannot be repeated.

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