# Answer on Statistics and Probability Question for SASHA

Question #5183

A survey was conducted to measure the number of hours per week adults spend on home

computers. In the survey, the number of hours was normally distributed, with a mean of 8

hours and a standard deviation of 1 hour. A survey participant is randomly selected. Find the

probability that the hours spent on the home computer by the participant are between 5.5 and

9.5 hours per week.

computers. In the survey, the number of hours was normally distributed, with a mean of 8

hours and a standard deviation of 1 hour. A survey participant is randomly selected. Find the

probability that the hours spent on the home computer by the participant are between 5.5 and

9.5 hours per week.

Expert's answer

Z-scores: (9.5-8)/1=1.5 and (5.5-8)/1=-2.5. Corresponding probabilities: 94.41%

and 0.62%, so the answer is P=94.41%-0.62%=93.79%.

and 0.62%, so the answer is P=94.41%-0.62%=93.79%.

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