Question #346038

**‘Bhartdarshan’ is an Internet-based travel agency wherein customers can see videos of the cities they plan to visit. The number of hits daily is a normally distributed random variable with a mean of 10,000 and a standard deviation of 2,400.**

**a. What is the probability of getting more than 12,000 hits?**

**b. What is the probability of getting fewer than 9,000 hits? **

Expert's answer

We have a normal distribution, "\\mu=10000, \\sigma=2400."

Let's convert it to the standard normal distribution,

"z=\\cfrac{x-\\mu}{\\sigma}.\\\\\n\\text{a. } z_1=\\cfrac{12000-10000}{2400}=0.83;\\\\\nP(X>12000)=P(Z>0.83)=\\\\\n=1-P(Z<0.83)=\\\\\n=1-0.7967=0.2033\n\\text{ (from z-table)}.\\\\\n\\text{b. } z_2=\\cfrac{9000-10000}{2400}=-0.42;\\\\\nP(X<9000)=P(Z<-0.42)=\\\\\n=0.3372\n\\text{ (from z-table)}."

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