Suppose that a class contains 15 boys and 30 girls and that 10 students are to be selected at random for a special assignment. Find the probability that exactly 3 boys will be selected.
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Expert's answer
2013-02-04T09:26:30-0500
There are
N = C(45,10) = 45!/(10!(45-10)!) = 3190187286
ways to choose 10 students from 45 students. Among them, there are
M = C(15, 3) = 15!/(3!(15-3)!) = 455
ways to choose 3 boys from 15 ones. Therefore, the probability that exactly 3 boys will be selected is
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