Answer to Question #178482 in Statistics and Probability for Wesley

Question #178482

a)   Two vacuum cleaner salesmen A and B must each make two calls per day, one in the morning and one in the afternoon. A has a probability 0.4 of selling a cleaner on any call, while B (a novice) has a probability 0.1 of a sale. A works independently of B and, for each salesman, morning and afternoon results are independent of each other.

Find the probability that, in one day:

    i.       A sells 2 cleaners

   i.       A sells just one cleaner

  ii.       B makes at least one sale

 iii.       Between them, A and B make exactly one sale




1
Expert's answer
2021-04-13T16:11:42-0400

i)

P(2) = 2!/(2!(2-2)!) *0.42*(1-0.4)2-2 = 0.16

ii)

P(1) = 2!/(1!(2-1)!) *0.41*(1-0.4)2-1 = 0.48

iii)

P(1) = 2!/(1!(2-1)!) *0.11*(1-0.1)2-1 = 0.18

iv)

P(1) = P(A sells 1) and P(B sells 0) or P(A sells 0 and B sells 1)

= (0.48*0.82) + (0.36*0.18)

= 0.4582



Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS