Question #17069

A box has 4 red balls and 3 green balls. If 3 balls are drawn with replacement, what is the probability of drawing 2 red and 1 green balls?

Expert's answer

Let's consider the following cases.

Let's consider the set of all possible evets:

& Omega; = {rrr rrg rgg ggg }

We see that |Ω| = 4. So, the probability of drawing 2 red and 1 green balls is

P = 1/4 = 0.25.

Let's consider the set of all possible evets:

& Omega; = {rrr rrg rgg ggg }

We see that |Ω| = 4. So, the probability of drawing 2 red and 1 green balls is

P = 1/4 = 0.25.

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