Answer to Question #14532 in Statistics and Probability for Quintin Warner

Question #14532
ASK # 38639 (use it when you're asking about your order) Order title: Statistics Subject: Math Category: Statistics and Probability Level: University Deadline: 2012-09-10 12:19 Price: 1 $ Task Hello, I need help with these problems. Directions for 9.26 It contain a graph portraying the decision criterion for a hypothesis test for a population mean, μ. The null hypothesis for each test is H0: μ= μ0: the test statistic is _ Z = X - μ0 ______ σ/ √ n The curve in each graph is the normal curve for the test statistic under the assumption that the null hypothesis is true. For each exercise, determine the a) rejection region. b) nonrejection region. c) critical value(s) d) significance level. e) Construct a graph similar to that in fig.9.5 on page 410 that depicts your results from parts (a)-(d). f) Identify the hypothesis test as two tailed, left tailed, or right tailed. Figure 9.5 _|__|__|____|____|______ -2 Nonreject 2 region Problem: 9.26 Reject H0/ do not reject h0 0.05 | __|______|___|___|____|__ -1.645 0 I dont know how to draw graph that connect to the problem however, it starts from far left and ends far right it has a concave down above 0. Directions for 9.58 IN each case, use the one-mean z test to perform the required hypothesis test about the mean, μ, of the population from which the sample was drawn. 9.58 - = 20, n = 24, σ = 4, H0: μ = not equal to 22, Ha:μ not equal to 22, α = 0.05 Direction for 9.140 a) Use the one-mean t-test to perform the required hypothesis test about the mean, μ, of the population from which the sample was drawn. b) Find (or estimate) the P-value and refer to table 9.12 on page 444 to determine the strength of the evidence against the null hypothesis. Table 9.12 Evidence P-value against H0 p > 0.10 weak or none 0.05 < p< 0.10 moderate - 0.01 < p < 0.05 strong - p < very strong - 9.150 Directions for 9.150 Perform each t-test, using either the critical-value approach or the P-value approach. 9.150 Active management of labor is a group of interventions designed to help reduce the length of labor and the rate of cesarean deliveries. Physicians from the department of obstetrics and gynecology at the university of new mexico health sciences center were interested in determining whether AML would also translate into a reduced coat for delivery. The results of their study can be found Active management of labor. According to the article, 200 AML deliveries had a mean cost of $2480 with a standard deviation of $766. At the time of the study, the average cost of having a baby in a U.S. hospital was $2528. At the 5% significance level, do the data provide sufficient evidence to conclude that, on average, AML reduces the cost of having a baby in a U.S. hospital ? Detailed explanation: NO Specific requirements: Please send in DOC only. And keep sentences Thank you
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