Question #13283

a container has 8 blue balls, 6 red balls, and 4 green balls. If 3 balls are drawn, with replacement, what is the probability that all three will be green?

Expert's answer

P = P1 * P2 * P3

If replacement occurs, P1 = P2 = P3 = 4 / (8 + 6 + 4) = 4 /

18.

P = 4^3 / 18^3 = 64 / 5832 = 8 / 729.

If replacement occurs, P1 = P2 = P3 = 4 / (8 + 6 + 4) = 4 /

18.

P = 4^3 / 18^3 = 64 / 5832 = 8 / 729.

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