61 798
Assignments Done
98%
Successfully Done
In May 2018

# Answer to Question #2179 in Linear Algebra for biju

Question #2179
Find the direction cosines of the perpendicular from the origin to the plane 3r.(2i &minus; 3j+ k) + 7 = 0.
When the plane is defined by he equation Ai - Bj+Ck + D =0, the directional cosines can be found by the following formulae:

&lt;img src=&quot;/cgi-bin/mimetex.cgi?l%20=%20%5Cfrac%7BA%7D%7B%5Csqrt%7BA%5E2+B%5E2+C%5E2%7D%7D%20=%20%5Cfrac%7B2%7D%7B%5Csqrt%7B2%5E2+%28-1%29%5E2+1%5E2%7D%7D%20=%20%5Cfrac%7B2%7D%7B%5Csqrt%7B6%7D%7D%20%5C%5C%20m%20=%20%5Cfrac%7BB%7D%7B%5Csqrt%7BA%5E2+B%5E2+C%5E2%7D%7D%20=%20-%20%5Cfrac%7B1%7D%7B%5Csqrt%7B6%7D%7D%20%5C%5C%20n%20=%20%5Cfrac%7BC%7D%7B%5Csqrt%7BA%5E2+B%5E2+C%5E2%7D%7D%20=%20%5Cfrac%7B1%7D%7B%5Csqrt%7B6%7D%7D&quot; title=&quot;l = \frac{A}{\sqrt{A^2+B^2+C^2}} = \frac{2}{\sqrt{2^2+(-1)^2+1^2}} = \frac{2}{\sqrt{6}} \\ m = \frac{B}{\sqrt{A^2+B^2+C^2}} = - \frac{1}{\sqrt{6}} \\ n = \frac{C}{\sqrt{A^2+B^2+C^2}} = \frac{1}{\sqrt{6}}&quot;&gt;

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!