# Answer to Question #13068 in Linear Algebra for Jess

Question #13068

You are given two finite dimensional subspaces of some inner product space. If one subspace is of lower dimension than the other, show whether there must exsist atleast one nonzero vector in the larger space that is orthogonal to all vectors in the smaller space.

Expert's answer

We can suppose that U,V are subspaces of some space X. dim(U)<dim(V).

If

we consider their intersection W, then choosing base w_1,...,w_k in W, be can

compeate it to the base of U by vectors u_1,...,u_m.

Then we can choose any

vector v_0 from V, that is not linear combination of vectors from W. Then

v_0, w_1,...,w_k, u_1,...,u_m are linearly independent, and vector v_0 can

be ortogonalized to all other these vectors, thus

it will be orthogonal to U.

If

we consider their intersection W, then choosing base w_1,...,w_k in W, be can

compeate it to the base of U by vectors u_1,...,u_m.

Then we can choose any

vector v_0 from V, that is not linear combination of vectors from W. Then

v_0, w_1,...,w_k, u_1,...,u_m are linearly independent, and vector v_0 can

be ortogonalized to all other these vectors, thus

it will be orthogonal to U.

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