# Answer to Question #45957 in Integral Calculus for victor

Question #45957

Integrate with respect to x :

∫2−2(x3−3x2+2x−5)dx

∫2−2(x3−3x2+2x−5)dx

Expert's answer

∫(2−2(x3−3x2+2x−5))dx=2∫dx-2∫x

^{3}dx+2∫3x^{2}dx-2∫2xdx+2∫5dx=2x-2x^{4}/4+6x^{3}/3-4x^{2}+10x+C=12x-4x^{2}+2x^{3 }- x^{4}/2+C, where C is an arbitrary real constant.Need a fast expert's response?

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