# Answer to Question #31053 in Integral Calculus for Aaron Okievs.

Question #31053

Integrate with respect to x: ∫ x 1/2 dx

a. (2/3)/3+c

b. (2x^(3/2))/3+c

c. 2x+c

d. 2

a. (2/3)/3+c

b. (2x^(3/2))/3+c

c. 2x+c

d. 2

Expert's answer

int; x 1/2 dx this is one of table integrals. As we know,& ∫ x^n dx=x^(n+1)/(n+1)+c

So in our case we obtain& ∫ x 1/2 dx=x^(1+1/2)/(1+1/2)+c=x^(3/2)/(3/2)+c=2x^(3/2)/3+c

Thus, the right answer is b.

So in our case we obtain& ∫ x 1/2 dx=x^(1+1/2)/(1+1/2)+c=x^(3/2)/(3/2)+c=2x^(3/2)/3+c

Thus, the right answer is b.

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