# Answer to Question #31050 in Integral Calculus for Aaron Okievs.

Question #31050

Integrate with respect to x: ∫ 3e^x dx

a. e^x+c

b. 3x+c

c. 3e^x+c

d. 3e^x

a. e^x+c

b. 3x+c

c. 3e^x+c

d. 3e^x

Expert's answer

At first we can rewrite the given integral as follows:

∫ 3e^x dx=3 ∫ e^x dx

Using table of integration we obtain that ∫ e^x dx=e^x+const then 3 ∫ e^xdx=3*( e^x+const )=3e^x+c

So the right answer is c. 3e^x+c

∫ 3e^x dx=3 ∫ e^x dx

Using table of integration we obtain that ∫ e^x dx=e^x+const then 3 ∫ e^xdx=3*( e^x+const )=3e^x+c

So the right answer is c. 3e^x+c

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