Answer to Question #28760 in Integral Calculus for Ankit
In interval notation we have the following:
So there are two intervals to be considered. Note that we exclude x=0 because we have x in the denominator, therefore it should be nonzero.
In this case we have
As x<0 this inequality has no solutions so we have empty set
Also we have x>0 so there's also empty set
Final answer is empty set.
Also we could do it another way.
This is false because 1/|x|>0 for real x
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