Question #7635

1) y"+4y=3x+e^2x, y(0)=0, y'(0)=1
2) y" + y' + y = (sin(x))^2, y(0)=1, y'(0)= -9/2
3) y"+ 3y' + 2y = 3e^-x - 10cos3x, y(0)=0, y'(0) = 2
how to solve it using undetermined coefficient for 2nd method... pls help me..

Expert's answer

Dear visitors!

We've created video explaining how to solve

2) y" + y' + y = sin^2x, y(0)=1, y'(0)= -9/2.

Please take a look!

We've created video explaining how to solve

2) y" + y' + y = sin^2x, y(0)=1, y'(0)= -9/2.

Please take a look!

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