The roots of the equation 4x-squared + kx = 9, differ by 5. Calculate the value(s) of k
1
Expert's answer
2013-04-08T11:19:59-0400
4x^2+kx-9=0. Let's divide both parts of the equation by 4. x^2+(k/4)x-9/4=0 Let A be one of the roots, then the other is A+5. Using Vieta's formulas, we have: (1) A+A+5=-k/4; (2) A*(A+5)=-9/4. Now we solve the (2) equation. A1=-1/2,A2=-9/2. So there are to value of k. If A=-1/2, then k=-16. (form (1) equation) If A=9/2, then k=16.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment