# Answer on Calculus Question for ong

Question #4638

Tom read a book from page 1 to page 59 without skipping any page.What is the sum of all the page number?

Expert's answer

we must find sum 1+2+3+4+....+58+59

it is a sum of arithmetic progression

with difference d=1 so S=n(a1+an)/2, where n is total number, a1, an - fisrt and

n-th summand so we have S=60*(1+59)/2=60*30=1800

it is a sum of arithmetic progression

with difference d=1 so S=n(a1+an)/2, where n is total number, a1, an - fisrt and

n-th summand so we have S=60*(1+59)/2=60*30=1800

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