# Answer on Calculus Question for shasha

Question #43001

Find the zeros of the polynomial function and state the multiplicity of each.

f(x) = 3(x + 9)2(x - 9)3

4, multiplicity 1; -9, multiplicity 3; 9, multiplicity 3

4, multiplicity 1; 9, multiplicity 1; -9, multiplicity 1

-9, multiplicity 3; 9, multiplicity 2

-9, multiplicity 2; 9, multiplicity 3

help me please

f(x) = 3(x + 9)2(x - 9)3

4, multiplicity 1; -9, multiplicity 3; 9, multiplicity 3

4, multiplicity 1; 9, multiplicity 1; -9, multiplicity 1

-9, multiplicity 3; 9, multiplicity 2

-9, multiplicity 2; 9, multiplicity 3

help me please

Expert's answer

The product equals zero only if at least one of the multipliers equal zero. Therefrom we get

(x+9)

x = -9 with multiplicity 2 and x=9 with multiplicity 3.

(x+9)

^{2 }= 0 or (x-9)^{3 }= 0x = -9 with multiplicity 2 and x=9 with multiplicity 3.

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