# Answer to Question #25707 in Calculus for Jeremy

Question #25707

Find the average value of the function over the given interval and every (all) value(s) of in the interval for which the function equals its average value.

f (x) = [4(x^2)+1]/x^2

over the interval [1,3]

f (x) = [4(x^2)+1]/x^2

over the interval [1,3]

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