# Answer on Calculus Question for hafeni

Question #18763

Find the derivative of the following:

y=(8-2x^2)(4-x)

y=(8-2x^2)(4-x)

Expert's answer

y'=(8-2x^2)'*(4-x)+(8-2x^2)*(4-x)'=-4x(4-x)-(8-2x^2)=-16x+4x^2-8+2x^2=6x^2-16x-8

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