Question #17849

Find the derivative of y=x-4 and name the rules that you used.
4x+7x^2 all divided by x, find the derivative.
Find the values of x for y=-5x^2-2x

Expert's answer

y'=(x-4)'=x'-4'=1-0=1

(2x+7x^2)/x=2+7x

2'+7x'=7

y=-5x^2-2x

y=0 at x=0 and x=0.4

(2x+7x^2)/x=2+7x

2'+7x'=7

y=-5x^2-2x

y=0 at x=0 and x=0.4

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