# Answer to Question #1712 in Calculus for vaish

Question #1712

Find the derivative. Simplify if possible.

f(t) = (sech(9e power t))2

f(t) = (sech(9e power t))2

Expert's answer

sech(z) = 2 (e

f'(t) = 2 [sech (9e

^{z}+ e^{-z})^{-1};[sech(z)]' = - 2 (e^{z}- e^{-z})/(e^{z}+ e^{-z})^{2}= - sech(z) tanh(z);f'(t) = 2 [sech (9e

^{t})]' sech(9e^{t}) = - 2 [9e^{t}]' sech^{2}(9e^{t}) tanh(9e^{t}) = - 18 e^{t}sech^{2}(9e^{t}) tanh(9e^{t})Need a fast expert's response?

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